![How can we solve this question, I proved the triangles (ABC and ADC) similar but still can't find that value : r/maths How can we solve this question, I proved the triangles (ABC and ADC) similar but still can't find that value : r/maths](https://preview.redd.it/how-can-we-solve-this-question-i-proved-the-triangles-abc-v0-iu641d1uyz7c1.jpeg?auto=webp&s=ee9287193404e79e8091d56ad26e99cb88ddef1a)
How can we solve this question, I proved the triangles (ABC and ADC) similar but still can't find that value : r/maths
a-c) fs-TA and (d) ns-TA spectra of AB-Me in ACN. Fig. 2 (a-c) fs-TA... | Download Scientific Diagram
![A plot of Q II = D AB + D AC − D ABC = 2D AB − D A:BC versus θ for 3... | Download Scientific Diagram A plot of Q II = D AB + D AC − D ABC = 2D AB − D A:BC versus θ for 3... | Download Scientific Diagram](https://www.researchgate.net/publication/235553942/figure/fig1/AS:671528035291148@1537116168411/A-plot-of-Q-II-D-AB-D-AC-D-ABC-2D-AB-D-ABC-versus-th-for-3-qubit-pure-states.png)
A plot of Q II = D AB + D AC − D ABC = 2D AB − D A:BC versus θ for 3... | Download Scientific Diagram
![In the given figure AB = AC, D is the mid point of AC, BD is the diameter of the A circle then prove - YouTube In the given figure AB = AC, D is the mid point of AC, BD is the diameter of the A circle then prove - YouTube](https://i.ytimg.com/vi/0swspzV1JII/maxresdefault.jpg)
In the given figure AB = AC, D is the mid point of AC, BD is the diameter of the A circle then prove - YouTube
If D and E are points on side AC and AB of a triangle ABC, such that AD = DE = EC =BC, then , show that , angle A : angle B = 1 : 3? - Quora
![In the figure AB, is tangent to circle O at point A, secant to BD intersects BD intersects circle O at points C and D. Acr AC= 70^\circ\ and\ arc\ CD= 110^\circ, In the figure AB, is tangent to circle O at point A, secant to BD intersects BD intersects circle O at points C and D. Acr AC= 70^\circ\ and\ arc\ CD= 110^\circ,](https://homework.study.com/cimages/multimages/16/figura2910903432415492295.jpg)
In the figure AB, is tangent to circle O at point A, secant to BD intersects BD intersects circle O at points C and D. Acr AC= 70^\circ\ and\ arc\ CD= 110^\circ,
![In the given figure, AB = AC , D is a point on AC and E an AB such that AD = ED = EC = BC, The ratio ∠ BAC : ∠ ABC =A. 1: 2B. 1: 3C. 2: 1D. 3: 1 In the given figure, AB = AC , D is a point on AC and E an AB such that AD = ED = EC = BC, The ratio ∠ BAC : ∠ ABC =A. 1: 2B. 1: 3C. 2: 1D. 3: 1](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/232806/content_740886.png)
In the given figure, AB = AC , D is a point on AC and E an AB such that AD = ED = EC = BC, The ratio ∠ BAC : ∠ ABC =A. 1: 2B. 1: 3C. 2: 1D. 3: 1
![16. In fig., AB divides ( angle D A C ) in the ratio 1 ( A B = D B . ) Determine the value of ( x ) 3 and 13 16. In fig., AB divides ( angle D A C ) in the ratio 1 ( A B = D B . ) Determine the value of ( x ) 3 and 13](https://toppr-doubts-media.s3.amazonaws.com/images/8201374/9f612af6-9b91-4a36-b172-28f1572205fd.jpg)
16. In fig., AB divides ( angle D A C ) in the ratio 1 ( A B = D B . ) Determine the value of ( x ) 3 and 13
![A complete and practical solution book for the common school teacher . FIG. 4. (AB X AC)(AB + AC)5 Let ABC be the given right-angled tri-angle. Produce AC to E, making CE = A complete and practical solution book for the common school teacher . FIG. 4. (AB X AC)(AB + AC)5 Let ABC be the given right-angled tri-angle. Produce AC to E, making CE =](https://c8.alamy.com/comp/2AJCYPH/a-complete-and-practical-solution-book-for-the-common-school-teacher-fig-4-ab-x-acab-ac5-let-abc-be-the-given-right-angled-tri-angle-produce-ac-to-e-making-ce-=ab-at-e-draw-ed-perpendicular-to-ceand-make-it-equal-to-ac-draw-dc-andbd-then-cd-=-cb-and-a-bcd-=-bc2theareaofabdeisequaltoaeabedor-ab-ac2-it-is-also-equal-tobcxcd-twice-the-a-abc-or-bc2-ab-x-ac-therefore-kab-ac2-=-4rbc2-whence-=-bc2-2-abx-ac-or-ab2-ac2-=-bc2-o-e-d-problem-300-given-the-right-angled-triangle-abc-the-base-actitude-bc-=-what-is-the-hypothenuse-solution-1-ac-=-4-2AJCYPH.jpg)