![calculus - Evaluation of a line integral using Green's Theorem where P, Q, and partial derivatives of P & Q are not continuous - Mathematics Stack Exchange calculus - Evaluation of a line integral using Green's Theorem where P, Q, and partial derivatives of P & Q are not continuous - Mathematics Stack Exchange](https://i.stack.imgur.com/Pt3Rq.png)
calculus - Evaluation of a line integral using Green's Theorem where P, Q, and partial derivatives of P & Q are not continuous - Mathematics Stack Exchange
How can this curvilinear integral of the first kind be calculated from the indicated curve [math]L[/math]: [math]\displaystyle\int_{L} 4 x y d s, \quad L=\left\{(x, y): y=\min \left(\frac{x^{2}}{a}, \sqrt{2 a^{2}-x^{2}}\right), x \geq 0\right\}[/math]? -
![SOLVED: (a) Sketch the graphs for the straight line path C : r(t) = ti + tj + tk; 0 <t < 1 and the curve path C2 r(t) = ti + SOLVED: (a) Sketch the graphs for the straight line path C : r(t) = ti + tj + tk; 0 <t < 1 and the curve path C2 r(t) = ti +](https://cdn.numerade.com/ask_images/0438b250e7c04cf39700397ca6fc2113.jpg)
SOLVED: (a) Sketch the graphs for the straight line path C : r(t) = ti + tj + tk; 0 <t < 1 and the curve path C2 r(t) = ti +
![real analysis - Misunderstanding Line (Curve) integral of first and second kind - Mathematics Stack Exchange real analysis - Misunderstanding Line (Curve) integral of first and second kind - Mathematics Stack Exchange](https://i.stack.imgur.com/c2Mz4.png)
real analysis - Misunderstanding Line (Curve) integral of first and second kind - Mathematics Stack Exchange
![Evaluate the line integral, where C is the given curve. Integral xyz^(2)ds C is the line segment from (-1, 2, 0) to (1, 3, 3). | Homework.Study.com Evaluate the line integral, where C is the given curve. Integral xyz^(2)ds C is the line segment from (-1, 2, 0) to (1, 3, 3). | Homework.Study.com](https://homework.study.com/cimages/multimages/16/part1_25052728416857945780.png)